SOLUTION: How much 15% HCl must be mixed with 8% HCl to produce 60mL of 9% solution?

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Question 568100: How much 15% HCl must be mixed with 8% HCl to produce 60mL of 9% solution?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How much 15% HCl must be mixed with 8% HCl to produce 60mL of 9% solution?
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HCL + HCL = HCL
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0.15x + 0.08(60-x) = 0.9*60mL
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Multiply thru by 100 to get:
15x + 8*60-8x = 9*60
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7x = 60
x = 8.5714 mL (amt. of 15% solution needed)
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Cheers,
Stan H.
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