SOLUTION: Write the fraction in terms of the LCM of the denominators.
9 over (x-1)^2 , 6 over x(x-1)
I thought I was supposed to find the LCD. How do you solve this?
I know the answer
Algebra ->
Expressions-with-variables
-> SOLUTION: Write the fraction in terms of the LCM of the denominators.
9 over (x-1)^2 , 6 over x(x-1)
I thought I was supposed to find the LCD. How do you solve this?
I know the answer
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Question 568018: Write the fraction in terms of the LCM of the denominators.
9 over (x-1)^2 , 6 over x(x-1)
I thought I was supposed to find the LCD. How do you solve this?
I know the answer is 9x over x(x-1)^2 , 6x-6 over x(x-1)^2
but I don't understand how to get to that. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Write the fraction in terms of the LCM of the denominators.
9 over (x-1)^2 , 6 over x(x-1)
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LCM = x(x-1)^2
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Rewrite each fraction with the LCM as its denominator
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[9/(x-1)^2] = [9x/LCM]
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[6/(x(x-1))] = [6(x+1)/LCM]
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Cheers,
Stan H.
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