SOLUTION: give exact and approximate solutions to three decimal places. y^2-8y+16=49 I have tried and cannot work it out correctly

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: give exact and approximate solutions to three decimal places. y^2-8y+16=49 I have tried and cannot work it out correctly      Log On


   

Question 567955: give exact and approximate solutions to three decimal places. y^2-8y+16=49
I have tried and cannot work it out correctly
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve:
y%5E2-8y%2B16+=+49 Subtract 49 from both sides.
y%5E2-8y-33+=+0 Factor the trinomial.
%28y%2B3%29%28y-11%29+=+0 Apply the zero product property.
y%2B3+=+0 or y-11+=+0
If y%2B3+=+0 Subtract 3 from both sides.
y+=+-3 This is one solution.
If y-11+=+0 Add 11 to both sides.
y+=+11 This the other solution.