SOLUTION: a jar contains $10.75 in dimes and quarters. If the number of quarters is seven more than the twice number of dimes. Determine the number of each coin
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Question 567802: a jar contains $10.75 in dimes and quarters. If the number of quarters is seven more than the twice number of dimes. Determine the number of each coin Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! a jar contains $10.75 in dimes and quarters. If the number of quarters is seven more than the twice number of dimes. Determine the number of each coin
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Value Equation: 10d + 25q = 1075 cents
Quantity Eq:: q = 2d + 7
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Substitute for "q" and solve for "d":
10d + 25(2d+7) = 1075
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10d + 50d + 175 = 1075
60d = 900
d = 15 (# of dimes)
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Solve for "q";
q = 2d+7
q = 2*15+7
q = 37 (# of quarters)
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Cheers,
Stan H.
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