SOLUTION: Proposition 1.8
If m is an integer, then (-m)+m=0
Proof
Let m be an element of Z
There exist a (-m) in an element Z Axiom 1.4
such that m+(-m)=0
m+(-m) = (-m)+m
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Proofs
-> SOLUTION: Proposition 1.8
If m is an integer, then (-m)+m=0
Proof
Let m be an element of Z
There exist a (-m) in an element Z Axiom 1.4
such that m+(-m)=0
m+(-m) = (-m)+m
Log On
Question 567801: Proposition 1.8
If m is an integer, then (-m)+m=0
Proof
Let m be an element of Z
There exist a (-m) in an element Z Axiom 1.4
such that m+(-m)=0
m+(-m) = (-m)+m Axiom 1.1(i)
= 0 Q.E.D
That's how I assume it is proven but it would be nice if someone could double check and make sure it is correct and also correct it. Thanks Answer by richard1234(7193) (Show Source):
You can put this solution on YOUR website! Solution is correct, however instead of "Axiom 1.4" and "Axiom 1.1" you should use "identity element" and "commutativity" or something along those lines, because no one (other than those using your textbook) will know what Axioms 1.1 and 1.4 are.
