SOLUTION: Given logk 3=7, logk 4=13, and logk 5=22, find logk (12/5k^3)^2

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Given logk 3=7, logk 4=13, and logk 5=22, find logk (12/5k^3)^2      Log On


   



Question 567785: Given logk 3=7, logk 4=13, and logk 5=22, find logk (12/5k^3)^2
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Use

The sum of the logs is the log of the product, the difference of the logs is the log of the quotient, and the log of something to a power is the power times the log:







to write:



Then substitute the values you were given plus the fact that to write:



And do the arithmetic.

John

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