SOLUTION: Find the values of the six trigonometric functions of θ if the terminal side of Ɵ lies on the given line in the specified quadrant y = {{{1/3}}}x, quadrant 3

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Question 567705: Find the values of the six trigonometric functions of θ if the terminal side of Ɵ lies on the given line in the specified quadrant
y = 1%2F3x, quadrant 3

Answer by Edwin McCravy(20063) About Me  (Show Source):
You can put this solution on YOUR website!
Find the values of the six trigonometric functions of θ if the terminal side of Ɵ lies on the given line in the specified quadrant
y = 1%2F3x, quadrant 3
Let's draw the line y = 1%2F3x




We want to find the six trig functions of the angle θ indicated by
the red arc.





Let's find a convenient point on that line in quadrant 3, the lower left quadrant.

We can avoid a fraction by choosing to find a point where x = -3, so
we substitute -3 for x in

y = 1%2F3x

y = 1%2F3(-3)

y = -1

So a convenient point on that line in quadrant 3 is (-3,-1)



Draw a vertical line from that point up to the x-axis:




That forms a right triangle in quadrant 3.  Let's label the upper
leg of the right triangle the same as the x-coordinate x=-3.
Let's label the green vertical leg of the triangle the same as the
y-coordinate y=-1. We label the hypotenuse of that triangle as r.


  
Next we calculate r by using the Pythagorean theorem:

r² = x² + y²
r² = (-3)² + (-1)²
r² = 9 + 1
r² = 10
r = sqrt%2810%29

So we label r as sqrt%2810%29



Then we remember the six trig ratios:

sin(θ) = y%2Fr = %28-1%29%2Fsqrt%2810%29 = -sqrt%2810%29%2F10
cos(θ) = x%2Fr = %28-3%29%2Fsqrt%2810%29 = -3sqrt%2810%29%2F10
tan(θ) = y%2Fx = %28-1%29%2F%28-3%29 = 1%2F3
sec(θ) = r%2Fx = sqrt%2810%29%2F%28-3%29 = -sqrt%2810%29%2F3 
csc(θ) = r%2Fy = sqrt%2810%29%2F%28-1%29 = -sqrt%2810%29
cot(θ) = x%2Fy = %28-3%29%2F%28-1%29 = 3

Edwin