You can put this solution on YOUR website! Factor, state prime if so
8xy^4+27x^4y
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= xy[8y^3 + 27x^3]
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You have the sum of squares:
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= xy(2y+3x)((2y)^2-(2y)(3x)+(3x)^2]
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= xy(4y^2-6xy+9x^2)
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Cheers,
Stan H.
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