SOLUTION: The local train is 25 miles down the track from the Central Station when the express leaves he station.The local train travels at a rate of 50 mi/hr and the express train travels a

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Question 567468: The local train is 25 miles down the track from the Central Station when the express leaves he station.The local train travels at a rate of 50 mi/hr and the express train travels at a rate of 80 mi/hr.Let n represent the number of hours since the express train left Central Station.
a.Write an expression that represents the express train's distance from Central Station in n hours.
b.When will the express train catch up with the local train?
Found 2 solutions by lwsshak3, stanbon:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
The local train is 25 miles down the track from the Central Station when the express leaves he station.The local train travels at a rate of 50 mi/hr and the express train travels at a rate of 80 mi/hr.Let n represent the number of hours since the express train left Central Station.
a.Write an expression that represents the express train's distance from Central Station in n hours.
b.When will the express train catch up with the local train?
**
n=travel time (hours) since express train left Central Station
distance=travel time*speed
a. Express train's distance from Central Station=80n
..
50n+25=80n (both trains travel the same distance)
30n=25
n=25/30=5/6 hrs
b.The express train catches up with the local train in 5/6 hrs or 50 minutes.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The local train is 25 miles down the track from the Central Station when the express leaves the station.
The local train travels at a rate of 50 mi/hr and the express train travels at a rate of 80 mi/hr.
Let n represent the number of hours since the express train left Central Station.
a.Write an expression that represents the express train's distance from Central Station in n hours.
distance = 80n miles
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b.When will the express train catch up with the local train?
Local train DAta:
distance = (80n - 25) miles ; rate = 50 mph ; time = (80n-25)/50 hr
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Express train DATA:
distance = 80n ; rate = 80 mph ; time = n hr.
=======
Equation:
time = time
n = (80n-25)/50
50n = 80n-25
30n = 25
n = 5/6 hrs
n = 50 minutes
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Cheers,
Stan H.