SOLUTION: There were 510 people at a play. The admission price was 2 for adults and 1 for children. The admission receipts were 810. How many adults and how many children attended?

Algebra ->  Matrices-and-determiminant -> SOLUTION: There were 510 people at a play. The admission price was 2 for adults and 1 for children. The admission receipts were 810. How many adults and how many children attended?      Log On


   

Question 567371: There were 510 people at a play. The admission price was 2 for adults and 1 for children. The admission receipts were 810. How many adults and how many children attended?
Answer by Maths68(1474) About Me  (Show Source):
You can put this solution on YOUR website!
Let
Adults = x
Children = 510-x
Total receipts = 810

Admission price for Adults = 2
Admission price for Children = 1


(Admission price for Adults)(Adults)+ (Admission price for Children)(Children) = Total receipts
(2)(x)+(1)(510-x)=810
2x+510-x=810
x=810-510
x=300

Adults = x = 300
Children = 510-x = 510-300 = 210

Check
======
300*2+210*1=810
600+210=810
810=810