SOLUTION: in the problem 3m^5-3m why is the answer 3m(m^2+1)(m+1)(m-1) instead of 3m(m+1)(m+1)(m+1)(m-1) ? I can not find any reason to have descending powers in factoring the difference of

Algebra ->  Square-cubic-other-roots -> SOLUTION: in the problem 3m^5-3m why is the answer 3m(m^2+1)(m+1)(m-1) instead of 3m(m+1)(m+1)(m+1)(m-1) ? I can not find any reason to have descending powers in factoring the difference of       Log On


   



Question 567207: in the problem 3m^5-3m why is the answer 3m(m^2+1)(m+1)(m-1) instead of 3m(m+1)(m+1)(m+1)(m-1) ? I can not find any reason to have descending powers in factoring the difference of two squares??
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!






You must have factored m^2 + 1 as (m+1)(m+1), which is incorrect. m^2 + 1 can't be factored into polynomials with real coefficients.