SOLUTION: If the width of a rectangle is 4 1/3 m and the perimeter is 9 7/15 m, what is the length of the base of the rectangle? Enter a fraction.

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: If the width of a rectangle is 4 1/3 m and the perimeter is 9 7/15 m, what is the length of the base of the rectangle? Enter a fraction.       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 56666: If the width of a rectangle is 4 1/3 m and the perimeter is 9 7/15 m, what is the length of the base of the rectangle?
Enter a fraction.
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
If the width of a rectangle is 4 1/3 m and the perimeter is 9 7/15 m, what is the length of the base of the rectangle?
Enter a fraction.
The 1st thing I would do is turn your mixed numbers into improper fractions:
width: 4 1/3= %283%2A4%2B1%29%2F3=13%2F3
perimeter: 9 7/15=%2815%2A9%2B7%29%2F15=142%2F15
Length:x
The formula for the perimeter of a rectangle is: highlight%28P=2W%2B2L%29, P=perimeter, W=width, and L=length
The equation you need to solve is:
142%2F15=2%2813%2F3%29%2B2x
142%2F15=26%2F3%2B2x Eliminate the fractions by multiplying everything by the LCD, 15:
15%28142%2F15%29=15%2826%2F3%29%2B15%282x%29
%2815%2F15%29142=%2815%2F3%29%2826%29%2B15%282x%29
142=5%2826%29%2B15%282x%29
142=130%2B30x
142-130=-130%2B130%2B30x
12=30x
12%2F30=30x%2F30
12%2F30=x
6%2A2%2F%286%2A5%29=x
2%2F5=x
The length is 2/5 m.
Happy Calculating!!!