SOLUTION: Find an equation of a line passing through (-1,0) and parallel to the line whose equation is given by x-y=1.

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Question 56643: Find an equation of a line passing through (-1,0) and parallel to the line whose equation is given by x-y=1.
Answer by funmath(2933) About Me  (Show Source):
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Find an equation of a line passing through (-1,0) and parallel to the line whose equation is given by x-y=1.
First find the slope of the line you've been given by putting it in slope intercept form:highlight%28y=mx%2Bb%29, where m=slope and (0,b)=y-intercept.
x-y=1
-x%2Bx-y=-x%2B1
-y=-x%2B1
-%28-y%29=-%28-x%2B1%29
y=x-1
The coeffiecient of x is understood to be 1. m=1
Parallel lines have the same slope, so our line has a slope of m=1 and goes through (x1,y1)=(-1,0).
We need the point slope formula: highlight%28y-y1=m%28x-x1%29%29
y-0=1%28x-%28-1%29%29
highlight%28y=x%2B1%29
Happy Calculating!!!