SOLUTION: The product of two consecutive odd integers is 58 less than the square of the next consecutive odd integer. Find the three integers. let 2x+1 = 1st odd integer 2x+3 = 2nd odd

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Question 566037: The product of two consecutive odd integers is 58 less than the square of the next consecutive odd integer. Find the three integers.
let 2x+1 = 1st odd integer
2x+3 = 2nd odd integer
2x+5 = 3rd odd integer
Please help me in completing the solution! THANKS :)
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
you can also work it out this way
let the consequtive odd numbers be x,x+2,x+4
x(x+2)=(x+4)^2-58
x^2+2x=x^2+8x+16-58
x^2 cancels off
2x-8x=16-58
-6x=-42
/6
x=7
the numbers are 7,9,11
CHECK
7*9=63
11^2=121
121-58=63