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| Question 566008:  A man borrowed rs. 35000 for one-year. One part of it was taken at the rate of 12% p.a. And the remaining part at the rate of 14% p.a. (simple interest). If he had to pay rs. 4460 as interest, then find the two parts which were borrowed at different rates.
 Answer by mananth(16946)
      (Show Source): 
You can put this solution on YOUR website! Investment Part I	12.00%		per annum	----x Investment part II	14.00%		per annum	----y
 The sum of the investments is 	$35,000.00
 The sum of individual interests = 	$4,460.00
 x		+	y	35000	------------------------1
 12.00%	x	+	14.00%	y	=	$4,460.00
 Multiply by 		100
 12	x	+	14	y	=	$446,000.00--------2
 
 Multiply (1) by			-12
 we get
 
 -12	x	-12	y	=		-420000.00
 
 Add this to (2)
 
 0	x	2	y	=		$26,000.00
 
 divide by		2
 
 y	=		$13,000.00		investment at
 Balance			$22,000.00					investment at
 CHECK
 $22,000.00	@	12.00%	$2,640.00
 $13,000.00	@	14.00%	$1,820.00
 Total	--------------------		$4,460.00
 
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