SOLUTION: a squared = (x+3)
b squared = 4(x+2)
c squared = 625
I have got to:
xsq+6x+9+4xsq+16x+16=625
then get stuck
Algebra ->
Pythagorean-theorem
-> SOLUTION: a squared = (x+3)
b squared = 4(x+2)
c squared = 625
I have got to:
xsq+6x+9+4xsq+16x+16=625
then get stuck
Log On
Question 566007: a squared = (x+3)
b squared = 4(x+2)
c squared = 625
I have got to:
xsq+6x+9+4xsq+16x+16=625
then get stuck Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! a squared = (x+3)
b squared = 4(x+2)
c squared = 625
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Pythagoras:
a^2 + b^2 = c^2
x+3+4x+8 = 625
5x+11 = 625
5x = 614
x = 122.8
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Cheers,
Stan H.
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