SOLUTION: Hello, please help me solve this equation: Two numbers differ by 2. Twice the smaller number is added to the larger number and the result is 6. Find the numbers. I have tried

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Hello, please help me solve this equation: Two numbers differ by 2. Twice the smaller number is added to the larger number and the result is 6. Find the numbers. I have tried       Log On


   

Question 565975: Hello,
please help me solve this equation: Two numbers differ by 2. Twice the smaller number is added to the larger number and the result is 6. Find the numbers.
I have tried solving this equation and i only got this:
Let the smaller number be 'x', and the larger number be 'y'.
x = y - 2 (since they differ by 2)
Equation 1) 2x + y = 6
2(y - 2) + y = 6
2y - 4 + y = 6
3y - 4 = 6
3y = 10
(thats all..)



Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Two numbers differ by 2. Twice the smaller number is added to the larger number and the result is 6. Find the numbers.
I have tried solving this equation and i only got this:
Let the smaller number be 'x', and the larger number be 'y'.
x = y - 2 (since they differ by 2)
Equation 1) 2x + y = 6
2(y - 2) + y = 6
2y - 4 + y = 6
3y - 4 = 6
3y = 10
Continue
y = 10%2F3
then
x = y - 2
x = 10%2F3 - 2
x = 10%2F3 - 6%2F3
x = 4%2F3
:
You know what you were doing, but because the solutions were not integers, you doubted.
:
Check our solution in the 2nd equation: 2x + y = 6
2(4%2F3) + 10%2F3 = 6
(8%2F3 + 10%2F3 = 6
18%2F3 = 6
6 = 6