SOLUTION: The area of a certain rectangle is 288yd2. The perimeter is 68yd. If you double the length and width, what will be the area and perimeter of the new rectangle?
Algebra ->
Rectangles
-> SOLUTION: The area of a certain rectangle is 288yd2. The perimeter is 68yd. If you double the length and width, what will be the area and perimeter of the new rectangle?
Log On
Question 565813: The area of a certain rectangle is 288yd2. The perimeter is 68yd. If you double the length and width, what will be the area and perimeter of the new rectangle? Answer by ad_alta(240) (Show Source):
You can put this solution on YOUR website! Doubling the length and width will also double the perimeter (which would be 136). The area would be (2w)(2l)=4wl=4A (for area 'A,' width 'w,' and length 'l'); thus, it would be multiplied by 4 (which would be 1152).
