SOLUTION: Please help me solve this equation: The length of a rectangle is 3 centimeters less than twice its width. Its area is 20 square centimeters. Find the dimensions of the rectangle.
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Question 565656: Please help me solve this equation: The length of a rectangle is 3 centimeters less than twice its width. Its area is 20 square centimeters. Find the dimensions of the rectangle. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Please help me solve this equation: The length of a rectangle is 3 centimeters less than twice its width. Its area is 20 square centimeters. Find the dimensions of the rectangle.
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Let the width be "x".
Then length is "2x-3"
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Area = width*length
x(2x-3) = 20
2x^2-3x-20 = 0
2x^2-8x+5x-20 = 0
2x(x-4)+5(x-4) = 0
(x-4)(2x+5) = 0
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Positive solution:
x = 4 cm
2x-3 = 5 cm
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Cheers,
Stan H.
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