SOLUTION: Can anyone help me with this one? thank you. The height of an object tossed upward with an initial velocity of 104 feet per second is given by the formula h= -16t^2 + 104t, w

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Question 56542This question is from textbook college algebra
: Can anyone help me with this one? thank you.

The height of an object tossed upward with an initial velocity of 104 feet per second is given by the formula h= -16t^2 + 104t, where h is the height in feet and t is the time in seconds. Find the time required for the object to return to its point of departure. This question is from textbook college algebra

Answer by funmath(2933) About Me  (Show Source):
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The height of an object tossed upward with an initial velocity of 104 feet per second is given by the formula h= -16t^2 + 104t, where h is the height in feet and t is the time in seconds. Find the time required for the object to return to its point of departure.
:
When the object hits the ground, h=0. So set the equation =0 and solve for t.
0=-16t%5E2%2B104t
0=-4t%284t-26%29
0=-4t
0%2F-4=-4t%2F-4
t=0, this is the time when the object was thrown.
0=4t-26
0%2B26=4t-26%2B26
26=4t
26%2F4=4t%2F4
6.5=t
The object will return to its point of departure at t=6.5 s.
Happy Calculating!!!