SOLUTION: the product of two consecutive integers is 16 less than the square of the next larger integer. what are the three integers? PLEASE SHOW ME HOW DID YOU GET THAT ANSWER STEP BY STEP

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: the product of two consecutive integers is 16 less than the square of the next larger integer. what are the three integers? PLEASE SHOW ME HOW DID YOU GET THAT ANSWER STEP BY STEP       Log On


   



Question 565387: the product of two consecutive integers is 16 less than the square of the next larger integer. what are the three integers? PLEASE SHOW ME HOW DID YOU GET THAT ANSWER STEP BY STEP THANKS
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Call the 3 integers +n+, +n%2B1+, and +n%2B2+
given:
+n%2A%28+n+%2B+1+%29+=+%28+n%2B2+%29%5E2+-+16+
+n%5E2+%2B+n+=+n%5E2+%2B+4n+%2B+4+-+16+
Subtract +n%5E2+ from both sides
+n+=+4n+%2B+4+-+16+
Subtract +4n+ from both sides
+-3n+=+4+-+16+
+-3n+=+-12+
Divide both sides by +-3+
+n+=+4+
+n+%2B+1+=+5+
+n+%2B+2+=+6+
The numbers are 4, 5, and 6
check:
+n%2A%28+n+%2B+1+%29+=+%28+n%2B2+%29%5E2+-+16+
+4%2A5+=+6%5E2+-+16+
+20+=+36+-+16+
+20+=+20+
OK