SOLUTION: How do I solve: Log x + log (13 -3x) = 1 (Bases are 10)
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Question 565317
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How do I solve:
Log x + log (13 -3x) = 1
(Bases are 10)
Answer by
scott8148(6628)
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adding logs means multiplying their arguments ___ and ___ 1 = log(10)
x(13 - 3x) = 10 ___ 13x - 3x^2 = 10 ___ 0 = 3x^2 - 13x + 10
factoring ___ 0 = (3x - 10)(x - 1)