SOLUTION: A rectangle has a width of 4X – 6, the length is triple this distance. IF the perimeter is 112. Find the value of X, the length, width and area of this rectangle.

Algebra ->  Rectangles -> SOLUTION: A rectangle has a width of 4X – 6, the length is triple this distance. IF the perimeter is 112. Find the value of X, the length, width and area of this rectangle.       Log On


   

Question 565084: A rectangle has a width of 4X – 6, the length is triple this distance. IF the perimeter is 112. Find the value of X, the length, width and area of this rectangle.

Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
P = 2L + 2W

112 = 2(12x - 18) + 2(4x - 6)

After doing the math, I got x = 5.

width = 4(5) - 6 or 14

length = 12(5) - 18 or 42

Area = length times width

Area = 14 times 42 or 588