SOLUTION: five times the sum of the digits of a two digit number equals the number. if the digits are reversed, it becomes nine more than the original number. what is the original number?
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Question 564765: five times the sum of the digits of a two digit number equals the number. if the digits are reversed, it becomes nine more than the original number. what is the original number?
You can put this solution on YOUR website! five times the sum of the digits of a two digit number equals the number. if the digits are reversed, it becomes nine more than the original number. what is the original number?
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Let the original number be 10t + u
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Equation:
5(t+u) = 10t+u
10u+t = 10t+u + 9
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Modify:
5t-4u = 0
9t-9u = -9
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Modify:
5t-4u = 0
t = u-1
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Substitute for "t" and solve for "u":
5(u-1)-4u = 0
u = 5
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Solve for "t":
t = u-1
t = 4
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Original number: 45
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Cheers,
Stan H.
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