SOLUTION: suppose a ball is thrown vertically up in the air so that the height of the ball after t seconds is s(t)=80t-16t^2. What is the height of the ball after 1 second?
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Question 564412: suppose a ball is thrown vertically up in the air so that the height of the ball after t seconds is s(t)=80t-16t^2. What is the height of the ball after 1 second? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! suppose a ball is thrown vertically up in the air so that the height of the ball after t seconds is s(t)=80t-16t^2. What is the height of the ball after 1 second?
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s(t)=80t-16t^2
Sub 1 for t
