SOLUTION: Solve: log4(x+3)=2 log7(x+2)=1-log7(x-4) Thanks
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Question 564323
:
Solve:
log4(x+3)=2
log7(x+2)=1-log7(x-4)
Thanks
Answer by
ad_alta(240)
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By definition, log_4 (x+3)=2 implies 4^2=x+3. Therefore x=13.
Similarly, raise both sides of the second equation to the 7th power. Then we get x+2=7(x-4)^{-1}. We should get x=5.