SOLUTION: x+2y+3z=6 y+2z=0 z=2

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Question 564241: x+2y+3z=6
y+2z=0
z=2
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
x+2y+3z=6
y+2z=0
z=2
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Solutions:
z = 2
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So, y + 2*2 = 0 ; So, y = -4
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Then, x + 2*-4 + 3*2 = 6
x - 8 + 6 = 6
x = 8
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Cheers,
Stan H.