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| Question 564215:  In 2006, the General Social Survey asked respondents whether they favored or opposed sex education in public schools. According to the survey results, 89% favored sex education in public schools. If two of the respondents are randomly selected, what is the probability that at least one favors sex education in public schools?
 How do I solve this problem?
 Thank you.  Colleen
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! According to the survey results, 89% favored sex education in public schools. If two of the respondents are randomly selected, what is the probability that at least one favors sex education in public schools? -----
 Binomial Problem with n = 2 and p(favor) = 0.89 ; P(not favor) = 0.11
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 P(1<= x <=2)
 = 1 - P(x = 0)
 = 1 - (0.11)^2
 = 0.9879
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 Cheers,
 Stan H.
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