SOLUTION: Please help me solve below;
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyc
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: Please help me solve below;
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyc
Log On
Question 564084: Please help me solve below;
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking? Answer by mananth(16946) (Show Source):
Difference in time= 3 hours
Cyclist I will have covered 18 m before Cyclist II starts
catch up distance= 18 m
catch up speed = 10 -6 mph
catch up speed = 4 mph
Catchup time = catchup distance/catch up speed
catch up time= 18 / 4
catch up time= 4.5 hours