SOLUTION: How would I solve the following logarithm? 2^x + 1 = 3^x - 4

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Question 563994: How would I solve the following logarithm?
2^x + 1 = 3^x - 4
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
How would I solve the following logarithm?
2^x + 1 = 3^x - 4
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What logarithm?
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2^x + 1 = 3^x - 4
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What are the exponents?
Is it 2%5Ex+%2B+1
or 2%5E%28x%2B1%29 ??