Question 563902: Hi,
Am stuck in solving the problem
3^x=2; 2^y=3 ; 5^z=3 then solve xyz=1
3^x=2
=>x=log base3 2
2^y=3
=>y=log base2 3
5^z=3
=>z=log base5 3
xyz= log base3 2 X log base2 3 x log base5 3
=>1xlog base5 3
=>log base5 3
Kindly guide me to proceed.
Regards,
AN Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 3^x=2; 2^y=3 ; 5^z=3 then solve xyz=1
3^x=2
=>x=log(2)/log(3)
--------------------------
2^y=3
=>y=log(3)/log(2)
--------------------------
5^z=3
=>z=log(3)/log(5)
-------------------------------
xyz= log(2)/log(3) X log(3)/log(2) x log(3)/log(5)
---
= log(3)/log(5)
----
= 0.6826
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Cheers,
Stan H.
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