SOLUTION: Please help with this. I can't understand the way my teacher is trying to explain.
Let "b" be a number such that log(b)3 = 1.5 and log(b)5=2.2
evaluate the following:
1. l
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: Please help with this. I can't understand the way my teacher is trying to explain.
Let "b" be a number such that log(b)3 = 1.5 and log(b)5=2.2
evaluate the following:
1. l
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Question 563705: Please help with this. I can't understand the way my teacher is trying to explain.
Let "b" be a number such that log(b)3 = 1.5 and log(b)5=2.2
evaluate the following:
1. log (b)15
2. log (b).6
3. log (b)125
4. log (b)(^3sqrt(3))^7
Thank you so much for your help Found 2 solutions by Alan3354, Tatiana_Stebko:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Let "b" be a number such that log(b)3 = 1.5 and log(b)5=2.2
evaluate the following:
1. log (b)15
15 = 3*5
Multiplying --> adding the logs
-----------------
2. log (b).6
0.6 = 3/5
Subtract logs when dividing
= log(3) - log(5) = -0.7
----------------
3. log (b)125
= 5*5*5
log(125) = log(5) + log(5) + log(5)
= 3*log(5)
Multiply the log by the exponent when raising to a power.
= 6.6
----------------
4. log (b)(^3sqrt(3))^7
If you mean
= Multiply by the exponent
Multiply the log by the exponent
--> 7*0.5 = 3.5
