SOLUTION: The length of a rectangle is 2cm more tham twice its width. If the perimeter of the rectangle is 52cm find the dimensions of the rectangle

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is 2cm more tham twice its width. If the perimeter of the rectangle is 52cm find the dimensions of the rectangle      Log On


   

Question 56362: The length of a rectangle is 2cm more tham twice its width. If the perimeter of the rectangle is 52cm find the dimensions of the rectangle
Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
P = 2(l+w)
l = 2w + 2
+P+=+2%28l%2Bw%29+
Substitute the valuse for the perimiter and the length into the equation so that you are dealing with only one variable
+52+=+2%282w+%2B2+%2B+w%29+
combine like terms
+52+=+2%283w+%2B2%29+
distribute
+52+=+6w+%2B+4+
subtract 4 from both sides
+48+=+6w+
divide by 6
+8+=+w+

+l+=+2w+%2B+2+
Plug in w=8
+l+=+2%288%29+%2B+2+
+l+=+16+%2B+2+
+l+=+18+