SOLUTION: hello, were solving linear equations by graphing, and i am having a little troble with this problem, -8x+12y=48 2x-3y=6. when i solve for the variables i get (-6,4) and (3,-2)

Algebra ->  Graphs -> SOLUTION: hello, were solving linear equations by graphing, and i am having a little troble with this problem, -8x+12y=48 2x-3y=6. when i solve for the variables i get (-6,4) and (3,-2)       Log On


   

Question 56354This question is from textbook algebra 2 equations graphs applications
: hello,
were solving linear equations by graphing, and i am having a little troble with this problem, -8x+12y=48 2x-3y=6. when i solve for the variables i get (-6,4) and (3,-2) so the lines are parallel, but my teacher informed me that the lines are not supposed to parallel. i am very confused and any help would be greatly appriciated. thank you very much! This question is from textbook algebra 2 equations graphs applications

Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
+-8x%2B12y=48 and +2x-3y=6+
get both equations in y=mx+b (point-slope form)
+12y+=+8x+%2B48+ and +-3y+=-2x+%2B6+
divide the first by 12 and divide the second by -3
+y+=+8x%2F12+%2B48%2F12+ and +y+=-2x%2F-3+%2B6%2F-3+
Reduce the fractions
+y+=+2x%2F3+%2B+4+ and +y+=2x%2F3+-2+
Notice how the m value IS exactly the same. so assuming your wrote the problem correctly .. they ARE parallel.
+graph%28+300%2C+300%2C+-5%2C+5%2C+-5%2C+5%2C+%282x%2F3%29%2B4%2C+%282x%2F3%29-2+%29+