SOLUTION: I have a few I am totally stuck on. #1)2/x+3 - 2x+3/x-1 = 6x-5/x^2+2x-3 Okay so I know that the LCD here is going to be (x+3) and (x+1) but I can not figure out how to d

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: I have a few I am totally stuck on. #1)2/x+3 - 2x+3/x-1 = 6x-5/x^2+2x-3 Okay so I know that the LCD here is going to be (x+3) and (x+1) but I can not figure out how to d      Log On


   



Question 563537: I have a few I am totally stuck on.
#1)2/x+3 - 2x+3/x-1 = 6x-5/x^2+2x-3
Okay so I know that the LCD here is going to be (x+3) and (x+1) but I can not figure out how to distribute it.
#2.)x^2-10/x^2-x-20 = 1 + 7/x-5
Here I have I think the LCD is (x-5) (x+4) but again am not being able to figure out how to distribute it properly.
#3)5y^(negative)2 +1=6y^(negative)1
No clue the negative exponents are really throwing me here....Thanks so much for your help

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!


LCD = (x+3) (x-1)
Multiply the equation by LCD

=

2x-2+-%282x%5E2%2B9x%2B9%29=6x-5
2x-2-2x%5E2-9x-9-6x%2B5=0
-2x%5E2-13x-6=0
2x%5E2%2B13x%2B6=0
2x%5E2%2Bx%2B12x%2B6
x%282x%2B1%29%2B6%282x%2B1%29=0
(x+6)(2x+1)=0
x=-6 OR -0.5
m.ananth@hotmail.ca