SOLUTION: Solve for x using logs. 2e^3x=4e^5x

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Question 563330: Solve for x using logs.
2e^3x=4e^5x
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
I'm assuming the x's are part of the exponent:
2e%5E%283x%29=4e%5E%285x%29
e%5E%283x%29%5E2=e%5E%285x%29%5E4
e%5E%289x%5E2%29=e%5E%28625x%5E4%29
taking the ln of both sides:
9x%5E2+=+625x%5E4+
9+=+625x%5E2+
9%2F625+=+x%5E2+
3%2F25+=+x+