SOLUTION: How many gallons of a 60% antifreeze solution must be mixed with 80 gallons of 25% antifreeze to get a mixture that is 50% antifreeze? Can you explain to me how to do this?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: How many gallons of a 60% antifreeze solution must be mixed with 80 gallons of 25% antifreeze to get a mixture that is 50% antifreeze? Can you explain to me how to do this?       Log On

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Question 563112: How many gallons of a 60% antifreeze solution must be mixed with 80 gallons of 25% antifreeze to get a mixture that is 50% antifreeze?
Can you explain to me how to do this?

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
(60%)(x) + (25%)(80) = (50%)(x + 80)

the sum of the amounts of antifreeze in the two solutions to be mixed, equals the amount of antifreeze in the final mixture