SOLUTION: On the coordinate grid of a map Jeff's house is located at (9,5). Hannah's house is at (-5,-5), Kenya's house is located at the midpoint between Jeff and Hannah's houses. What i

Algebra ->  Length-and-distance -> SOLUTION: On the coordinate grid of a map Jeff's house is located at (9,5). Hannah's house is at (-5,-5), Kenya's house is located at the midpoint between Jeff and Hannah's houses. What i      Log On


   



Question 563100: On the coordinate grid of a map Jeff's house is located at (9,5). Hannah's house is at (-5,-5), Kenya's house is located at the midpoint between Jeff and Hannah's houses. What is the distance between Hannah's house to Kenya's house (in mileage).

Note:.... I came up with a distance of 17.2 units, but 1) not sure that is right and 2) need for the answer to be in miles.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
On the coordinate grid of a map Jeff's house is located at (9,5). Hannah's house is at (-5,-5), Kenya's house is located at the midpoint between Jeff and Hannah's houses. What is the distance between Hannah's house to Kenya's house (in mileage).
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d+=+sqrt%28diffy%5E2+%2B+diffx%5E2%29+=+sqrt%2810%5E2+%2B+14%5E2%29+=+sqrt%28296%29
d =~ 17.2 units from Jeff's house to Hannah's house
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--> 17.2/2 = 8.6 units to Kenya's house
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There's no info given on miles. No way to convert units to miles.