SOLUTION: when I have the equation square root of(x+5)=2*square root of (x-3) + 1 how do I start that?

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Question 562701: when I have the equation square root of(x+5)=2*square root of (x-3) + 1 how do I start that?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
when I have the equation square root of(x+5)=2*square root of (x-3) + 1 how do I start that?
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√(x+5)=2√(x-3)+1
square both sides
x+5=4(x-3)+4√(x-3)+1
distribute, combine like terms and isolate radical
x+5=4x-12+4√(x-3)+1
-3x+16=4√(x-3)
square both sides again
9x^2-96x+256=16(x-3)=16x-48
9x^2-112x+304=0
(x-4)(9x-76)=0
x=4
or
x=76 (reject, does not check-extraneous root)