SOLUTION: how do i solve (2t-3)^2-4(2t-3)+3=0
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Question 561998
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how do i solve (2t-3)^2-4(2t-3)+3=0
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scott8148(6628)
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factoring ___ [(2t - 3) - 3][(2t - 3) - 1] = 0
(2t - 3) - 3 = 0
(2t - 3) - 1 = 0