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| Question 561589:  I am currently learning Systems of Linear Equations and Inequalities the problem I am currently working on is:
 3x+5y=14
 x-2y=-10
 I have no idea where to start, or how to work the problem
 Answer by fcabanski(1391)
      (Show Source): 
You can put this solution on YOUR website! You can use substitution.  Solve the second equation for x: x=2y-10 | Substitute that x value into the first equation and solve for y:
 3(2y-10)+5y=14 |Distribute the 3:
 6y-30+5y=14 | Combine the y's, add 30 to both sides:
 11y=44 | divide both sides by 11:
 y = 4 |substitute that into the second equation that you solved for x:
 x=2(4)-10 = 8-10 = -2
 
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