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Question 561529: I am a 3-digit even number. The sum of my digits is six times my
last digit. The product of my first and second digits is a perfect square number. The
difference between my first digit and my third digit is the same as the number of sides of
a triangle. My second digit is the same as the number of sides on a pentagon. Who am I
Answer by richard1234(7193)   (Show Source):
You can put this solution on YOUR website! "My second digit is the same as the number of sides on a pentagon"
5, so we have _5_.
"The product of my first and second digits is a perfect square number"
The only digit d for which 5d is a perfect square is 5, so we have 55_.
"The sum of my digits is six times my last digit"
If the last digit is d, then 10+d = 6d, 5d = 10, d = 2.
Therefore the number is 552.
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