SOLUTION: 1. a box containing 6 red balls and 4 green balls. how many ways can 2 balls be drawn at the time if a. the balls are of any color? b. in the balls are of the same color? c. if

Algebra ->  Probability-and-statistics -> SOLUTION: 1. a box containing 6 red balls and 4 green balls. how many ways can 2 balls be drawn at the time if a. the balls are of any color? b. in the balls are of the same color? c. if       Log On


   



Question 561104: 1. a box containing 6 red balls and 4 green balls. how many ways can 2 balls be drawn at the time if
a. the balls are of any color?
b. in the balls are of the same color?
c. if the two balls are different color?
2. a sample of 12 students will be taken from a class with 26 girls and 15 boys. In how many ways can a sample be taken if
a. there must be equal number of boys and girls
b. gender is not a consideration
c. 2 girls are fixed elements and the rest are all boys

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
1. a box containing 6 red balls and 4 green balls. how many ways can 2 balls be drawn at the time if
a. the balls are of any color?

The number of ways to choose 2 from 10 balls, C(10,2) = 45


b. in the balls are of the same color?

The number of ways to choose 2 red balls from 6 red balls, C(6,2) = 15 +
The number of ways to choose 2 green balls from 4 green balls, C(4,2) = 2.
Answer 15+2=17. 



c. if the two balls are different color?

For each of the 6 ways to choose the red ball, there are 4 ways
to choose the green ball.  So that 6*4 or 24


2. a sample of 12 students will be taken from a class with 26 girls and 15 boys. In how many ways can a sample be taken if
a. there must be equal number of boys and girls

For each of the C(26,6) ways to choose the 6 girls from the 26, there are
C(15,6) ways to choose the 6 boys from the 15.  Thats C(26,6)*C(15,6)
or 1152301150


b. gender is not a consideration

The number of ways to choose 12 students from 38 students, C(38,12)
or 2707475148

c. 2 girls are fixed elements and the rest are all boys

The number of ways to choose 10 boys from 15 boys, C(15,10) = 3003.

Edwin