You can put this solution on YOUR website! Solve the following equation for x
2cos^2x+sinx=1 for 0 < x < 360 deg
2(1-sin^2x)+sinx=1
2-2sin^2x+sinx=1
-2sin^2x+sinx+1=0
2sin^2x-sinx-1=0
(2sinx+1)(sinx-1)=0
..
2sinx+1=0
sinx=-1/2
x=210º and 330º (in quadrants III and IV where sin<0)
..
sinx-1=0
sinx=1
x=90º
..
ans:
x=210º, 330º and 90º
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