SOLUTION: The length of a rectangler picture is 5 inches greater than twice the width. If the perimeter is 112 inches, find the dimensions of the frame.

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Question 560476: The length of a rectangler picture is 5 inches greater than twice the width. If the perimeter is 112 inches, find the dimensions of the frame.
Found 2 solutions by solver91311, stanbon:
Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website!

If a rectangle with perimeter has a length that is units longer (or shorter if ) than times the width, ,

Then knowing that the Perimeter is given by:

,

make the substitution:

Then solve for

For your problem: , , and . Do the arithmetic.

John

My calculator said it, I believe it, that settles it

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
The length of a rectangler picture is 5 inches greater than twice the width. If the perimeter is 112 inches, find the dimensions of the frame.
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Let width = x
Then length = 2x+5
----
Perimeter = 2(length + width)
----
112 = 2(2x+5 + x)
56 = 3x+5
3x = 51
x = 17 inches (width)
2x+5 = 2*17+5 = 39 inches (length)
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Cheers,
Stan H.
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