Question 560460: solve for x:
log base 3 (7x+4)-log base 3 of 2 = 2logbase3 of X Found 2 solutions by stanbon, josmiceli:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! solve for x:
log base 3 (7x+4)-log base 3 of 2 = 2logbase3 of X
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log3(7x+4) - log3(2) = log3(x^2)
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log3[(7x+4)/2] = log3(x^2)
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[(7x+4)/2] = x^2
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2x^2 - 7x - 2 = 0
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x = [7 +- sqrt(49-4*2*-2)]/4
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x = [7 +- sqrt(49+16)]/4
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Positive solution:
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x = [7 + sqrt(65)]/4
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x = 3.7656..
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Cheers,
Stan H.
You can put this solution on YOUR website!
Use the rule
Use the rule
Use the quadratic formula
and, taking the (-) square root,
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Using ,
OK
Using
I have to reject this solution for because of the
right side. It is impossible to raise the base to
some power ( + or - ) that will result in ,
or any negative number.
So, is the only solution