SOLUTION: Find the remaining sides of a 45° — 45° — 90° triangle if the shorter sides are each 7/8.

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Question 560342: Find the remaining sides of a 45° — 45° — 90° triangle if the shorter sides are each 7/8.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the remaining sides of a 45° — 45° — 90° triangle if the shorter sides are each 7/8.
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Sides are (7/8) ; (7/8) ; x
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x is the hypotenuse.
x^2 = (7/8)^2 + (7/8)^2
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x^2 = 2*(7/8)^2
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x = (7/8)*sqrt(2)
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Cheers,
Stan H.