SOLUTION: train A and train B are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train B is traveling at 48 miles per hour. Train A passes

Algebra ->  Inequalities -> SOLUTION: train A and train B are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train B is traveling at 48 miles per hour. Train A passes       Log On


   

Question 560227: train A and train B are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train B is traveling at 48 miles per hour. Train A passes a station at 5:25 a.m. If train B passes the same station at 5:55 a.m., what time will train B catch up to train A?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Train A 40 mph
Train B 48 mph
Train A 05:25
Train B 05:55
Difference in time=00:30=> 0.5 hours
Train A will have covered 20 miles before Train B starts from station
catch up distance= 20 miles
catch up speed = 48 -40 mph
catch up speed = 8 mph
Catchup time = catchup distance/catch up speed
catch up time= 20 / 8
catch up time= 2.5 hours
Add 2 hours 30 minutes to 5:55
=8:25 am