SOLUTION: Are the following lines parallel, peGiven f(x) = x2 – x + 7, find f(0).rpendicular, or neither? L1 with equation x – 6y = 30 L2 with equation 6x + y = 6 A) Parallel B) Perpe

Algebra ->  Graphs -> SOLUTION: Are the following lines parallel, peGiven f(x) = x2 – x + 7, find f(0).rpendicular, or neither? L1 with equation x – 6y = 30 L2 with equation 6x + y = 6 A) Parallel B) Perpe      Log On


   

Question 56003: Are the following lines parallel, peGiven f(x) = x2 – x + 7, find f(0).rpendicular, or neither? L1 with equation x – 6y = 30 L2 with equation 6x + y = 6
A) Parallel
B) Perpendicular
C) Neither
Can some one PLEASE HELP!!!!
Given g(x) = 4x – 3, find g(3a).
Given f(x) = 4x + 4, find f(0).1.
Solve the system by addition. 5x – 3y = 13 4x – 3y = 11
Can someone out there feel sorry for me and help me Please while I still have hair in my head!!!!

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Hi nearlyhairless, lets see what we can do to:
Are the following lines parallel, perpendicular, or neither? L1 with equation x – 6y = 30 L2 with equation 6x + y = 6
A) Parallel
B) Perpendicular
C) Neither
Put the equations in slope intercept form: y=mx%2Bb, m=slope and (0,b)= y-intercept. Parallel lines have equal slopes and perpendicular lines have slopes that are negative reciprocals (opposite signs and upside down).
L1) x-6y=30
-x%2Bx-6y=-x%2B30
-6y=-x%2B30
-6y%2F-6=-x%2F-6%2B30%2F-6
y=highlight%281%2F6%29x-5
slope=m=+1/6
L2) 6x%2By=6
-6x%2B6x%2By=-6x%2B6
y=highlight%28-6%29x%2B6
m=-6/1
(B) Perpendicular
:
Given
f%28x%29=x%5E2-x%2B7
find f(0).
Let x=0
f%280%29=%280%29%5E2-%280%29%2B7
f%280%29=0-0%2B7
highlight%28f%280%29=7%29
:
Given g(x) = 4x – 3, find g(3a).
Let x=3a
g(3a)=4(3a)-3
g(3a)=12a-3
:
Given f(x) = 4x + 4, find f(0)
let x=0
f(0)=4(0)+4
f(0)=0+4
highlight%28f%280%29=4%29
:
Solve the system by addition.
L1) 5x – 3y = 13
L2) 4x – 3y = 11
Multiply L2 by -1 and add L1 and L2
-1(4x-3y)=-1(11)
-4x+3y=-11
-----------
5x-3y=13
-4x+3y=-11
____________
x+0y=2
x=2
Substitute x=2 into L1 and solve for x.
5(2)-3y=13
10-3y=13
-10+10-3y=-10+13
-3y=3
-3y/-3=3/-3
y=-1
The solution is (x,y)=(2,-1)
Happy Calculating!!!
funmath and a littleweirdmath