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>>...my tens digit is 3 more than my ones digit...<<
equation 1. t = u+3
>>...my hundreds is 1 less than my tens digit...<<
equation 2. h = t-1
>>...the sum of my digits is 20...<<
equation 3. h+t+u = 20
Use equation 1 to substitute u+3 for t in equation 2:
equation 2. h = t-1
h = (u+3)-1
h = u+3-1
equation 4. h = u+2
Use equation 1 and equation 4 to substitute u+3 for t
and u+2 for h in equation 3:
equation 3. h+t+u = 20
(u+2)+(u+3)+u = 20
u+2+u+3+u = 20
3u+5 = 20
3u = 15
equation 5. u = 5
Use equation 5 to substitute 5 for u in equation 4
equation 4. h = u+2
h = 5+2
h = 7
Use equation 5 to substitute 5 for u in equation 1
equation 1. t = u+3
t = 5+3
t = 8
So the digits are h = 7, t = 8, and u = 5 and
therefore the number is 785.
Edwin